Team India, registering its name in the pages of history, achieved the biggest win in its Test cricket history against South Africa on this day in the year 2019. It is noteworthy that the second match of that tour of South Africa is being played at MCA Stadium, Pune (10-14 October). In this match, India defeated the visiting team by a margin of innings and 137 runs.

Talking about the match, India won the toss and decided to bat. While opening, Rohit was out early after scoring 14 runs, but Mayank Agarwal played a brilliant inning of 108 runs, while Cheteshwar Pujara contributed 58 runs.

So, after a brilliant start by the top order, captain Virat Kohli played the biggest innings in his Test cricket history, putting the nail in the coffin of India’s victory. In the match, Kohli batted in great style and played a brilliant inning of 254* runs in 236 balls. After this, on the strength of Ajinkya Rahane’s 59 and Ravindra Jadeja’s innings of 91 runs, India declared the first innings at 601 runs at the loss of 5 wickets.

African batting had collapsed in front of Indian bowling.

After this, when South Africa came out to bat in the first innings, on the second ball of the second over, opener Aiden Markram was out LBW against Umesh Yadav without opening the account. So Dean Elgar could also score only 6 runs. However, captain Faf du Plessis scored 64 runs and Keshav Maharaj scored 72 runs. South Africa’s first innings was reduced to 275 runs in 105.4 overs.

After this, India asked South Africa to follow up. After this, South Africa, who came to bat, was all out for just 189 runs in the second innings in front of the excellent bowling of India, and had to face defeat in the match by an innings and 137 runs.